Vector Cross Product Magnitude
The cross product produces a new vector perpendicular to both inputs, with a magnitude equal to the area of the parallelogram they span — this is exactly the quantity behind torque (force cross lever arm), angular momentum, and the normal vector to a surface defined by two edge vectors.Unlike the dot product, the cross product depends on the order of the vectors (a×b = −b×a) and only exists in this simple component form in three dimensions, which is why it is written out here component by component rather than through a matrix function.
The cross product components are c_x = a_2b_3−a_3b_2, c_y = a_3b_1−a_1b_3, c_z = a_1b_2−a_2b_1, and its magnitude is |c| = sqrt(c_x²+c_y²+c_z²). where a_1c, a_2c, a_3c are the components of vector a, b_1c, b_2c, b_3c are the components of vector b, and c_x, c_y, c_z are the components of the resulting cross-product vector.
The x-component of the cross product comes from the "opposite" y and z components of the two vectors, following the cyclic pattern of the determinant expansion.
The y-component follows the same cyclic pattern shifted one step.
The z-component completes the cycle.
The magnitude of the resulting vector is its length by the Pythagorean theorem, and equals the area of the parallelogram spanned by a and b.
Results
A nonzero cross-product magnitude confirms the two vectors are not parallel; the value itself equals the area of the parallelogram they span, which is exactly the moment arm effect used when computing torque as r×F. If the two input vectors were parallel, every component of c would come out zero, signaling no perpendicular "twisting" effect between them.